Answer
$\frac{dy}{dx}=(\ln 7)(4-2x)7^{4x-x^2}$
Work Step by Step
$y=7^{4x-x^2}$
$\frac{dy}{dx}=\frac{d(7^{4x-x^2})}{dx}$
$\frac{dy}{dx}=7^{4x-x^2} (\ln 7)\frac{d(4x-x^2)}{dx}$
$\frac{dy}{dx}=7^{4x-x^2} (\ln 7 )(4-2x)$
$\frac{dy}{dx}=(\ln 7)(4-2x)7^{4x-x^2}$
