Answer
$$2x+2xy'+2y+3y^2y'=0.$$
Work Step by Step
By using the product rule: $(uv)'=uv'+u'v $, we have
$$2x+2xy'+2y+3y^2y'=0.$$
So the right answer is $$2x+2xy'+2y+3y^2y'=0.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.8 Implicit Differentiation - Preliminary Questions - Page 152: 3
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