Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.6 Trigonometric Functions - Exercises - Page 140: 38

Answer

See the details below.

Work Step by Step

For $ y=\sin x $, we have $$ y'=\cos x, \quad y''=-\sin x $$ and hence $ y''=-y $. For $ y=\cos x $, we have $$ y'=-\sin x, \quad y''=-\cos x $$ and hence $ y''=-y $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.