Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 123: 54

Answer

$ f(x)=g(x)=x $ $ f'(x)=g'(x)=\frac{d}{dx}(x)=1$ $(\frac{f}{g})'=\frac{f'g-fg'}{g^{2}}=\frac{1\times x-x\times1}{x^{2}}=0$ $\frac{f'}{g'}=\frac{1}{1}=1$ We see that $(\frac{f}{g})'\ne \frac{f'}{g'}$

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