Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 121: 6



Work Step by Step

Using the product rule, we have $\frac{dy}{dt}=\frac{d}{dt}(t-8t^{-1})(t+t^{2})+(t-8t^{-1})\frac{d}{dt}(t+t^{2})$ $=(1+\frac{8}{t^{2}})(t+t^{2})+(t-\frac{8}{t})(1+2t)$ $=t+t^{2}+\frac{8}{t}+8+t+2t^{2}-\frac{8}{t}-16$ $=3t^{2}+2t-8$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.