#### Answer

$(f-g)'(1)$ =-2.
$ (3f + 2g)'(1) $ = 19.

#### Work Step by Step

Derivative properties state that $(f-g)'$ = $f' - g'$ and $(f+g)'$ = $f' + g'$.
Thus, $(f-g)'(1)$ = $ f'(1) - g'(1) $ = 3 - 5 = -2.
$ (3f + 2g)'(1) $ = $ 3f'(1) + 2g'(1)$ = 3 (3) + 2 (5) = 19.