## Calculus (3rd Edition)

$(f-g)'(1)$ =-2. $(3f + 2g)'(1)$ = 19.
Derivative properties state that $(f-g)'$ = $f' - g'$ and $(f+g)'$ = $f' + g'$. Thus, $(f-g)'(1)$ = $f'(1) - g'(1)$ = 3 - 5 = -2. $(3f + 2g)'(1)$ = $3f'(1) + 2g'(1)$ = 3 (3) + 2 (5) = 19.