Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.2 The Derivative as a Function - Exercises - Page 115: 49


(a) $\frac{d}{dt}ct^3=3ct^2$. (b) $\frac{d}{dz}(5z+4cz^2)=5+8cz $. (c) $\frac{d}{dy}(9c^2y^3-24c)=27c^3y^2 $.

Work Step by Step

Since $ c $ is constant, we have (a) $\frac{d}{dt}ct^3=3ct^2$. (b) $\frac{d}{dz}(5z+4cz^2)=5+8cz $. (c) $\frac{d}{dy}(9c^2y^3-24c)=27c^3y^2 $.
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