Answer
For all $\epsilon>0$, exists $\delta>0$ so that
if $|x-0|
Work Step by Step
$f(x)=x^2+x^3$
We have:
Consider $|x|<1$
We have:
$|x^2+x^3-0|=|x^2(x+1)|$
$|f(x)-0|=|x^2(x+1)|0$, exists $\delta>0$ so that
if $|x-0|
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.9 The Formal Definition of a Limit - Exercises - Page 93: 22
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