Answer
$\delta=0.1$
$\epsilon=0.03$
$\epsilon=0.01$
$\delta=0.04$
Work Step by Step
$f(x)=\dfrac{1}{x^2}$
We have:
$1.90$, exists $\delta>0$ so that
if $|x-2|
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.9 The Formal Definition of a Limit - Exercises - Page 82: 8
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