Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.7 Limits at Infinity - Exercises - Page 82: 9



Work Step by Step

Divide the numerator and denominator by $x^{4}$, which is the highest power of x occurring in the denominator. Then, we get $\lim\limits_{x \to \infty}\frac{3x^{2}+20x}{2x^{4}+3x^{3}-29}=\lim\limits_{x \to \infty}\frac{\frac{3}{x^{2}}+\frac{20}{x^{3}}}{2+\frac{3}{x}-\frac{29}{x^{4}}}=\frac{0+0}{2+0-0}=0$
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