## Calculus (3rd Edition)

$$\lim _{h \rightarrow -2} (4a\ h +7 a)=-a$$
Given $$\lim _{h \rightarrow -2} (4a\ h +7 a), \ \ \ a \ \ \text{is constant}$$ let $$f(h) = (4a\ h +7 a)$$ Since, we have $$f(-2)= (-8 a+7 a)=-a$$ So, we get \begin{aligned} L&=\lim _{h \rightarrow -2} (4a\ h +7 a)\\ &= (-8a\ +7 a)\\ &= -a \end{aligned}