Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 68: 74



Work Step by Step

\begin{align*} \lim _{x \rightarrow 2} \sqrt{x^3+4x}&= \sqrt{2^3+4(2)}\\ &= \sqrt{16}\\ &=4. \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.