Answer
$$4$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 2} \sqrt{x^3+4x}&= \sqrt{2^3+4(2)}\\
&= \sqrt{16}\\
&=4.
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 68: 74
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