Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 66: 14


See the proof below.

Work Step by Step

Since for $4^x $, $ 4>1$, then by Theorem 3, $4^x $ is continuous and hence the function $$ f(x)= \tan 4^x=\frac{\sin 4^x}{\cos 4^x}$$ is continuous.
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