Answer
$=\dfrac {1}{3}$
Work Step by Step
$\lim _{x\rightarrow \dfrac {1}{3}}\left( 3x^{3}+2x^{2}\right) =3\times \left( \dfrac {1}{3}\right) ^{3}+2\times \left( \dfrac {1}{3}\right) ^{2}=3\times \dfrac {1}{27}+2\times \dfrac {1}{9}=\dfrac {1}{9}+\dfrac {2}{9}=\dfrac {3}{9}=\dfrac {1}{3}$
