Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.1 Limits, Rates of Change, and Tangent Lines - Exercises - Page 45: 14



Work Step by Step

We are given the function: $y(t)=\sqrt{3t+1}$ The average rate of change on $[t_0,t_1]$ is: $\dfrac{\Delta y}{\Delta t}=\dfrac{y(t_1)-y(t_0)}{t_1-t_0}$ The instantaneous rate of change is the limit of the average rate of change. In order to estimate the instantaneous rate of of change at $t=1$, consider intervals $[t_1,t_0],[t_0,t_1]$ for $t_1$ close to $t_0$, where $t_0=1$: $[0.9,1]$: $\dfrac{\Delta y}{\Delta x}=\dfrac{y(0.9)-y(1)}{0.9-1}=\dfrac{\sqrt{3(1.9)+1}-\sqrt{3(1)+1}}{-0.1}\approx 0.76461594$ See table From the table we find that the instantaneous rate of of change at $t=1$ is approximately $075$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.