Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 16 - Multiple Integration - 16.6 Change of Variables - Preliminary Questions - Page 904: 3



Work Step by Step

By using Theorem 1, we have $$ \operatorname{Area}(G(\mathcal{D}))=|\operatorname{Jac}(G)| \operatorname{Area}(\mathcal{D}) $$ And thus $$ \operatorname{Area}(G(\mathcal{R}))=|\operatorname{Jac}(G)| \operatorname{Area}(\mathcal{R})=4\times 9=36. $$
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