#### Answer

$e^2$

#### Work Step by Step

Since we have $f(u,v)=rse^{r+s}$, then at $r=1$ and $s=1$, we have:
$$f(u,v)=(1)(1)e^{1+1}=e^2.$$

Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

$e^2$

Since we have $f(u,v)=rse^{r+s}$, then at $r=1$ and $s=1$, we have:
$$f(u,v)=(1)(1)e^{1+1}=e^2.$$

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