Answer
$h(3,8,2) = 6$.
$h(3,-2,-6) = \frac{-1}{6}$.
Work Step by Step
We are given the function:
$h(x,y,z)=xyz^{-2}$
We plug in the points to find the function values:
$h(3,8,2) = (3)(8)(2)^{-2} = (3)(8)(\frac{1}{4}) = (3)(2) = 6$
$h(3,-2,-6) = (3)(-2)(-6)^{-2} = (3)(-2)(\frac{1}{36}) = \frac{-6}{36} = \frac{-1}{6}$
