Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.1 Functions of Two or More Variables - Exercises - Page 763: 2


$$\frac{3}{10}, \quad -\frac{2}{13}.$$

Work Step by Step

Since $ g(x,y)=\frac{y}{x^2+y^2}$, then $$ g(1,3)=\frac{3}{1+9}=\frac{3}{10}=\frac{3}{10}.$$ $$ g(3,-2)=\frac{-2}{9+4}=-\frac{2}{13}.$$
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