Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - Chapter Review Exercises - Page 702: 32

Answer

The correct answer is (b) $\left( {{\bf{u}} + {\bf{w}}} \right)\cdot\left( {{\bf{v}} \times {\bf{w}}} \right)$.

Work Step by Step

Consider (a) ${\bf{v}} \times \left( {{\bf{u}} + {\bf{w}}} \right)$. By properties of the cross product we have ${\bf{v}} \times \left( {{\bf{u}} + {\bf{w}}} \right) = {\bf{v}} \times {\bf{u}} + {\bf{v}} \times {\bf{w}}$ Since the cross products of two vectors is a vector, and the sum of two vectors is a vector, we conclude that ${\bf{v}} \times \left( {{\bf{u}} + {\bf{w}}} \right)$ is a vector. Consider (b) $\left( {{\bf{u}} + {\bf{w}}} \right)\cdot\left( {{\bf{v}} \times {\bf{w}}} \right)$. Since the sum of two vectors is a vector, so $\left( {{\bf{u}} + {\bf{w}}} \right)$ is a vector. Since the cross products of two vectors is a vector, so $\left( {{\bf{v}} \times {\bf{w}}} \right)$ is a vector. Since the dot product of two vectors is a scalar, we conclude that $\left( {{\bf{u}} + {\bf{w}}} \right)\cdot\left( {{\bf{v}} \times {\bf{w}}} \right)$ is a scalar. Consider (c) $\left( {{\bf{u}} \times {\bf{w}}} \right) + \left( {{\bf{w}} - {\bf{v}}} \right)$. Since $\left( {{\bf{u}} \times {\bf{w}}} \right)$ is a vector and $\left( {{\bf{w}} - {\bf{v}}} \right)$ is a vector, the sum $\left( {{\bf{u}} \times {\bf{w}}} \right) + \left( {{\bf{w}} - {\bf{v}}} \right)$ is a vector. Hence, the correct answer is (b) $\left( {{\bf{u}} + {\bf{w}}} \right)\cdot\left( {{\bf{v}} \times {\bf{w}}} \right)$.
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