## Calculus (3rd Edition)

$$e_v= \left\langle -\frac{2}{\sqrt{29}},\frac{5}{\sqrt{29}}\right \rangle .$$
Since $v=\langle -2,5\rangle$, then the unit vector in the direction of $v$ is $e_v$, which is given by $$e_v=\frac{v}{\|v\|}=\frac{\langle -2,5\rangle}{\sqrt{4+25}}=\left\langle -\frac{2}{\sqrt{29}},\frac{5}{\sqrt{29}}\right \rangle .$$