Answer
$$ e_v= \left\langle -\frac{2}{\sqrt{29}},\frac{5}{\sqrt{29}}\right \rangle .$$
Work Step by Step
Since $ v=\langle -2,5\rangle $, then the unit vector in the direction of $ v $ is $ e_v $, which is given by
$$ e_v=\frac{v}{\|v\|}=\frac{\langle -2,5\rangle}{\sqrt{4+25}}=\left\langle -\frac{2}{\sqrt{29}},\frac{5}{\sqrt{29}}\right \rangle .$$
