$(1, \pi/2,-2) \Longrightarrow (0, 1,-2) $.
Work Step by Step
We have $$ r=1, \quad \theta =\pi/2, \quad z=-2.$$ Now, we have $$ x=r\cos \theta=0,$$ $$ y=r\sin \theta=1,$$ $$ z=-2.$$ So, $(1, \pi/2,-2) \Longrightarrow (0, 1,-2) $.
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