## Calculus (3rd Edition)

$$\left(\frac{x}{2}\right)^{2}+\left(\frac{y}{4}\right)^{2}+\left(\frac{z}{6}\right)^{2}=1.$$
By observing Figure 15(A), we get that $$a=2, \quad b=4, \quad c=6.$$ Using the equation of the ellipsoid (page 691) and the above variables, we get: $$\left(\frac{x}{2}\right)^{2}+\left(\frac{y}{4}\right)^{2}+\left(\frac{z}{6}\right)^{2}=1.$$