Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.4 The Cross Product - Exercises - Page 677: 16

Answer

$$ (2\mathbf{i}-3 \mathbf{j}+4\mathbf{k}) \times(\mathbf{i}+\mathbf{j}-7\mathbf{k})\\ =17\mathbf{i}+18\mathbf{j}+5\mathbf{k} $$

Work Step by Step

$$ (2\mathbf{i}-3 \mathbf{j}+4\mathbf{k}) \times(\mathbf{i}+\mathbf{j}-7\mathbf{k})\\=2( \mathbf{k}+7\mathbf{j})-3(-\mathbf{k}-7\mathbf{i})+4(\mathbf{j}-\mathbf{i})\\ =17\mathbf{i}+18\mathbf{j}+5\mathbf{k} $$
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