## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Preliminary Questions - Page 635: 1

#### Answer

(a) Hyperbola (b) Parabola (c) Ellipse (d) No conic section.

#### Work Step by Step

(a) The equation can be written in the form $\frac{x^2}{12/4}-\frac{y^2}{12/9}=1$ Thus, it is a hyperbola. (b) The equation can be written in the form $y^2=(4/9)x$ Thus, it is a parabola. (c) The equation can be written in the form $\frac{x^2}{12/4}+\frac{y^2}{12/9}=1$ Thus, it is an ellipse. (d) This equation can not be formed to look like one of the conic section formulas in this chapter. Thus, it does not correspond to any conic section.

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