Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.5 Conic Sections - Exercises - Page 635: 7


$$ \left(\frac{x}{6}\right)^{2}+\left(\frac{y}{3}\right)^{2}=1. $$

Work Step by Step

Translating the center of the ellipse $$ \left(\frac{x-8}{6}\right)^{2}+\left(\frac{y+4}{3}\right)^{2}=1 $$ to the origin, leads to the new ellipse $$ \left(\frac{x}{6}\right)^{2}+\left(\frac{y}{3}\right)^{2}=1. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.