Calculus (3rd Edition)

$(1,\pi/2)$ and $(-1,-\pi/2).$
We know that the point is located at $x=0$ and $y=1$. This is the same as the point on the unit circle at 90 degrees from the origin. Thus, we know that $r=1$ and $\theta=\pi/2$. The polar representation of $(0,1)$ is $(1,\pi/2)$ and in terms of negative radial representation, it is $(-1, \pi/2-\pi)=(-1,-\pi/2).$