Answer
$$r= 2\sec(\theta-(\pi/9)).$$
Work Step by Step
The polar form of the equation of the line $\mathcal{L}$ is given by
$$r=d\sec(\theta-\alpha)=2\sec(\theta-(\pi/9)).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.3 Polar Coordinates - Exercises - Page 619: 43
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