Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.3 Polar Coordinates - Exercises - Page 617: 13

Answer

$$ x^2+y^2-2y=0$$

Work Step by Step

Recall that $x^2+y^2=r^2$ and $r\sin \theta=y$: \begin{align*} r&=2\sin \theta \\ r^2 &=2r\sin \theta \\ x^2+y^2&=2y \end{align*} then $$ x^2+y^2-2y=0$$
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