Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - 11.3 Convergence of Series with Positive Terms - Exercises - Page 557: 59


The series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.

Work Step by Step

We have $$ \lim_{k\to \infty}4^{1/k}=4^0=1.$$ Hence, the series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.