#### Answer

The series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.

#### Work Step by Step

We have
$$ \lim_{k\to \infty}4^{1/k}=4^0=1.$$
Hence, the series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

The series $\sum_{k=1}^{\infty} 4^{1/k} $ diverges.

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