#### Answer

Converges

#### Work Step by Step

Given $$\sum_{n=1}^{\infty} \frac{1}{n2^n}$$
We compare the given series with the series $\displaystyle\sum_{n=1}^{\infty} \frac{1}{2^n }$, which is a convergent series ( geometric with $|r|<1$) and for $n>1$
$$ \frac{1}{n2^n}\leq\frac{1}{2^n} $$
Then $\displaystyle\sum_{n=1}^{\infty} \frac{1}{n2^n}$ also converges.