Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - 11.2 Summing and Infinite Series - Preliminary Questions - Page 546: 2

Answer

$$1/2.$$

Work Step by Step

We have $$ \frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\cdots\\ =\frac{1}{4}(1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\cdots) .$$ This is a gemetric series with the sum $$\frac{1/4}{1-(1/2)}=\frac{1}{4-2}=1/2.$$
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