## Calculus (3rd Edition)

We have (a) $\lim_{n\to \infty} \frac{n^2}{n^2+1}=1$. (b) $\lim_{n\to \infty} 2^n=\infty$. (c) $\lim_{n\to \infty} (\frac{-1}{2})^{n}=0$. Since $$\lim_{n\to \infty} (\frac{-1}{2})^{n}=0$$ then the right answer is (c).