## Calculus (3rd Edition)

$$y=\pm\sqrt{1+t}$$
Since the equation of the isocline of the slope $c$ is given by $$F(t,y)=c$$ then the equation of the isocline of the slope $c=1$ is: $$y^2-t=1.$$ Solve for $y$: $$y=\pm\sqrt{1+t}$$