Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 31: 38

Answer

$$f(\theta)=\sin \left(2\left(\theta-\frac{\pi}{2}\right)+\pi\right)+2,\ \ \ \ \ \ [0,2\pi]$$

Work Step by Step

We are given the function: $$f(\theta)=\sin \left(2\left(\theta-\frac{\pi}{2}\right)+\pi\right)+2,\ \ \ \ \ \ [0,2\pi]$$ We sketch the function over the given interval as shown below.
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