## Calculus (3rd Edition)

$$f(\theta)=\sin \left(2\left(\theta-\frac{\pi}{2}\right)+\pi\right)+2,\ \ \ \ \ \ [0,2\pi]$$
We are given the function: $$f(\theta)=\sin \left(2\left(\theta-\frac{\pi}{2}\right)+\pi\right)+2,\ \ \ \ \ \ [0,2\pi]$$ We sketch the function over the given interval as shown below.