Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.4 Trigonometric Functions - Exercises - Page 29: 3


(a) $ \dfrac{180}{\pi} \approx 57.3^{\circ}$ (b)$\, 60^{\circ}$ (c) $\dfrac{75}{\pi} \approx23.87^{\circ}$ (d) $225^{\circ}$

Work Step by Step

Recall: $$\text{Angle in degree } = \text{Angle in radian } \times \dfrac{180}{\pi}$$ (a) $$\theta= 1 \times \dfrac{180}{\pi} = \dfrac{180}{\pi} \approx 57.3^{\circ}$$ (b) $$\theta= \dfrac{\pi}{3} \times \dfrac{180}{\pi} = 60^{\circ}$$ (c) $$\theta=\dfrac{5}{12}\times \dfrac{180}{\pi}=\dfrac{75}{\pi} \approx23.87^{\circ}$$ (d) $$\theta = \dfrac{-3\pi}{4} \times \dfrac{180}{\pi} = -135^{\circ}$$ $\because \theta \text{ is equivalent to } \theta+360^{\circ}$ $$-135 = -135+360 =225^{\circ}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.