## Calculus (3rd Edition)

$f(x)= (x-a)^3$ (other answers are possible.)
We need to find a function that is symmetric with respect to the point $(a,0)$. We know that the odd cubic function $f(x)=x^3$ is symmetric with respect to the origin $(0,0)$. If we shift this function by $a$ units to the right, we will obtain the desired function. That is, the function $f(x)= (x-a)^3$ is symmetric with respect to $(a,0)$.