Answer
This is an even function. The zeroes are -2, 0, and 2.
Work Step by Step
To find whether a function is even or odd, plug in -x and evaluate the result.
$f(-x)=(-x)^2(4-(-x)^2)$
$f(-x)=x^2(4-x^2)$
Because the result is the same as $f(x)$, this is an even function.
To find the zeroes, use the zero product property.
$x^2=0$
$x=0$
$4-x^2=0$
$x^2=4$
$x=2,-2$
