Calculus 10th Edition

$y=-\dfrac{3}{5}x+\dfrac{14}{5}$
Point $(-2,4)$ $;$ $m=-\dfrac{3}{5}$ Use the point-slope form of the equation of a line formula, which is $y-y_{0}=m(x-x_{0})$, where $(x_{0},y_{0})$ is a point through which the line passes and $m$ is its slope. Substitute the known values into the formula and evaluate to obtain the equation of the line: $y-y_{0}=m(x-x_{0})$ $y-4=-\dfrac{3}{5}(x+2)$ $y-4=-\dfrac{3}{5}x-\dfrac{6}{5}$ $y=-\dfrac{3}{5}x-\dfrac{6}{5}+4$ $y=-\dfrac{3}{5}x+\dfrac{14}{5}$ The sketch of the line is shown below: