Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - Review Exercises - Page 676: 4

Answer

See below

Work Step by Step

We can make two different sets and then conjoin them, $a_n = 2n$ $[2,4,6,8,10]$ And $a_n=n+5$ $[6,7,8,9,10]$ We create fractions with $2n$ on top, $n+5$ on the bottom $$a_1 =2/6 =1/3$$ $$a_2 = 4/7 $$ $$a_ 3=6/8 =3/4$$ $$a_4 =8/9 $$ $$a_5 = 10/10 = 1$$
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