Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - Review Exercises - Page 676: 12

Answer

3

Work Step by Step

As n grows large, $2/(n^2-1)$ grows closer and closer to zero. Thus $\lim\limits_{n \to 0} 3- 2/(n^2-1) = 3- 0 = 3$
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