Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.6 Exercises - Page 633: 2

Answer

Proof, See work below

Work Step by Step

Verify the formula $\frac{(2k-2)!}{(2k)!} = \frac{1}{(2k)(2k-1)} $ Simplify the factorial $\frac{(2k-2)!}{(2k)(2k-1)(2k-2)!}$ Cancel out the factorial terms $ \frac{1}{(2k)(2k-1)}$ Verified
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