Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.4 Exercises - Page 617: 36

Answer

Diverges

Work Step by Step

We are given the series as: $\Sigma_{n=1}^{\infty} \dfrac{n^2}{n^3+1}$ We can see that the degree of the denominator is equal to $k=3$ and the degree of the numerator is equal to $j=2$. This implies that $j \gt k$ Also, the condition $ j=2 \geq k-1=2$ has been satisfied. Hence, we can conclude that the given series diverges.
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