Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.2 Exercises - Page 602: 60

Answer

Please see step-by-step

Work Step by Step

(a) The infinite series $\displaystyle \sum_{n=1}^{\infty}a_{n}$ diverges if the sequence of partial sums $\{S_{n}\}$ diverges. $ S_{n}=a_{1}+a_{2}+\cdot \cdot +a_{n}$ gets arbitrarily large in magnitude (positive or negative). The sum of a finite number of terms is a finite number A. Let k be the index of the last deleted term ( the deleted terms are among $\{a_{1},a_{2},...,a_{k}\}$. Then for $n\geq k$, the new partial sums are $(S_{k+1}-A),(S_{k+2}-A),,(S_{k+3}-A)...$ which are obtained by subtracting a finite number A from numbers that grow in magnitude without bound. This sequence diverges, so the new series will diverge. (b) Let S be the sum of the series. Let k be the index of the last deleted term ( the deleted terms are among $\{a_{1},a_{2},...,a_{k}\}$. As in part (a), observe, for $n\geq k$, the new partial sums : $(S_{k+1}+A),(S_{k+2}+A),(S_{k+3}+A)...$ This seqence is obtained by adding a finite number A to terms that converge to S. The sequence converges to S+A, so the new series will converge.
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