Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 565: 68

Answer

\[\boxed{\begin{array}{*{20}{c}} x&{\frac{{{{\left( {\ln x} \right)}^4}}}{x}} \\ {10}&{2.8110} \\ {{{10}^2}}&{4.4976} \\ {{{10}^4}}&{0.7196} \\ {{{10}^6}}&{0.03643} \\ {{{10}^8}}&{0.001151} \\ {{{10}^{10}}}&{0.00002811} \end{array}}\]

Work Step by Step

$$\eqalign{ & \frac{{{{\left( {\ln x} \right)}^4}}}{x} \cr & {\text{Completing the table of values:}} \cr & x = 10 \to \frac{{{{\left( {\ln 10} \right)}^4}}}{{10}} \approx \frac{{28.1101}}{{10}} \approx 2.8110 \cr & x = {10^2} \to \frac{{{{\left( {\ln {{10}^2}} \right)}^4}}}{{100}} \approx \frac{{449.7619}}{{100}} \approx 4.4976 \cr & x = {10^4} \to \frac{{{{\left( {\ln {{10}^4}} \right)}^4}}}{{{{10}^4}}} \approx \frac{{7196.1916}}{{10000}} \approx 0.7196 \cr & x = {10^6} \to \frac{{{{\left( {\ln {{10}^6}} \right)}^4}}}{{{{10}^6}}} \approx \frac{{36430.7201}}{{1000000}} \approx 0.03643 \cr & x = {10^8} \to \frac{{{{\left( {\ln {{10}^8}} \right)}^4}}}{{{{10}^8}}} \approx \frac{{115139}}{{100000000}} \approx 0.001151 \cr & x = {10^{10}} \to \frac{{{{\left( {\ln {{10}^{10}}} \right)}^4}}}{{{{10}^{10}}}} \approx \frac{{281101}}{{10000000000}} \approx 0.00002811 \cr} $$ \[\boxed{\begin{array}{*{20}{c}} x&{\frac{{{{\left( {\ln x} \right)}^4}}}{x}} \\ {10}&{2.8110} \\ {{{10}^2}}&{4.4976} \\ {{{10}^4}}&{0.7196} \\ {{{10}^6}}&{0.03643} \\ {{{10}^8}}&{0.001151} \\ {{{10}^{10}}}&{0.00002811} \end{array}}\]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.