Answer
$14-2\ln3$
Work Step by Step
$\int_1^3\frac{2x^{2}+3x-2}{x}dx$
$=\int_1^32x+3-\frac{2}{x}dx$
$=(x^{2}+3x-2\ln x)|_1^3$
$=(9+9-2\ln3)-(1+3-2\ln1)$
$=18-2\ln3-4$
$=14-2\ln3$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 513: 62
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