Answer
True
Work Step by Step
We know that $$k\int_a^b h(x)dx =\int_a^b k h(x)dx$$
where k is a constant.
Given that $$\int_a^b[f(x)-g(x)]dx=A$$
Multiplying both sides by -1 gives, $$-\int_a^b[f(x)-g(x)]dx=-A$$ or $$\int_a^b-[f(x)-g(x)]dx=-A$$ $$\int_a^b[g(x)-f(x)]dx=-A$$
