Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.3 Exercises - Page 423: 82

Answer

True

Work Step by Step

We are given $y'=xy-2y+x-2$. We can rearrange it as $\frac{dy}{dx}=(x-2)y+(x-2)1 = (x-2)(y+1)$. Or, $\frac{dy}{y+1}=(x-2)dx$ which is the separate variables form.
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