Answer
$56$
Work Step by Step
$\int ^{8}_{0}\left( 3+x\right) dx=\int ^{8}_{0}\left( 3dx+xdx\right) =\left( 3x+\dfrac {x^{2}}{2}\right) ]^{8}_{0}=\left( 3\times 8+\dfrac {8^{2}}{2}\right) -\left( 3\times 0+\dfrac {0^{2}}{2}\right) =24+32=56$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 313: 43
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