Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises - Page 302: 69

Answer

$$\frac{272}{15}$$ $$or$$ $$18.133$$

Work Step by Step

We are asked to evaluate the integral given using properties of even and odd functions. We are given: $$\int_{-2}^{2} x^2(x^2+1) dx$$ If we look at a picture of the graph (enclosed below), we will see that the function is an even function. With even functions, we can double the integral while changing the bottom limit from -2 to 0, leaving us with: $$2\int_{0}^{2} x^2(x^2+1) dx$$ Evaluation: $2\int_{0}^{2} x^4+x^2 dx$ $2* _{0}^{2} | \frac{1}{5}x^5 + \frac{1}{3}x^3$ $2(\frac{32}{5} + \frac{8}{3})$ $2(\frac{96}{15} + \frac{40}{15})$ $$=\frac{272}{15}$$
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